The sum of three numbers is 127. the second number is 4 times the third. the first number is 7 more than the third. what are the numbers?

  27, 80, 20

Step-by-step explanation:

Let t represent the third number. The second number is 4 times that, 4t. The first number is 7 more than the third, so is (t+7). The sum of the three numbers is ...

  (t+7) + 4t + t = 127

  6t +7 = 127 . . . . . .  collect terms

  6t = 120 . . . . . . . . .subtract 7

  t = 20 . . . . . . . . . . . divide by 6; the 3rd number is 20

  4t = 80 . . . . the second number is 80

  t+7 = 27 . . . the first number is 27

The three numbers are 27, 80, and 20.

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.