During a three-day premiere, a theater must sell an average of 200 tickets per night to make a profit. for the first two nights, 206 and 185 tickets were sold. how many tickets must be sold for the third night for the theater to make a profit?

200 X 3 = 600 tickets total need to be sold

600-206-185 = 209 tickets need to be sold the third night

209

Step-by-step explanation:

Given

200 tickets needed to be sell per night to make a profit.

For first two nights 206 and 185 tickets were sold

Let x be the tickets sold on third day

therefore their average must be equal to 200

600=206+185+x

x=209

Therefore tickets sold in third day is  209

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )