Anormal distribution has a mean of 80 and a standard deviation of 14. determine the value above which 80 percent of the values will occur.

80% of the values will occurs above 68.24.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Determine the value above which 80 percent of the values will occur.

This is the value of X when Z has a pvalue of 1-0.8 = 0.2.

So this is X when Z = -0.84.

80% of the values will occurs above 68.24.

nope

step-by-step explanation:

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: