![V = \frac{9\pi}{8} \int_0^\pi (3-4cos(2x)+cos(4x)) dx \\ \\ V = \frac{9\pi}{8} |_0^\pi 3x -2sin(2x)+\frac{1}{4}sin(4x) \\ \\ V = \frac{9\pi}{8}[3\pi - 0] \\ \\ V = \frac{27 \pi^2}{8}](/tpl/images/0405/1934/0d366.png)
Find the volume v obtained by rotating the region bounded by the curves about the given axis.
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Mathematics, 05.12.2019 21:31 ariannecama
Find the volume v obtained by rotating the region bounded by the curves about the given axis.
y = 3 sin2(x), y = 0, 0 ≤ x ≤ π; about the x−axis
Answers: 1
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