One angle of a rhombus measures 108°, and the shorter diagonal is 9 inches long. approximately how long is the side of the rhombus? (hint: diagonals of a rhombus bisect the angles.)

This is the concept of geometry, to get the length of the side of the rhombus we shall use the cosine rule;
c^2=a^2+b^2-2abcosC
c=9
C=(360-2*108)/2=[360-216]/2=72
Thus;
since the sides of a rhombus are equal, then we can let the length of the sides be x;
9^2=x^2+x^2+2*x*xcos72
81=2x^2+0.62x^2
81=2.62x^2
hence;
x^2=81/2.62
x^2=30.94
x=sqrt(30.94)
x=5.56
The side lengths are each 5.56 inches long

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