Rectangle a is similar to rectangle b. rectangle b has sides that are 4 times longer than rectangle a. what is the relationship between the perimeters of rectangles a and b a. the perimeter of rectangle a is equal to the perimeter of
rectangle b.
b. the perimeter of rectangle b is 4 times the perimeter of rectangle a.
c. the perimeter of rectangle b is 8 times the perimeter of rectangle a.
d. the perimeter of rectangle b is one-fourth the perimeter of
rectangle a.

The answer is option B. 
let the sides of rectangle A be x and y
so the sides of rectangle B will be 4x and 4y
perimeter of recyangle A= 2(l+b)
                                           =2(x+y)
                                           =2x+2y
perimeter of rectangle B=2(l+b)
                                          = 2(4x+4y)
                                          =2*4(x+y)
                                          = 8 (x+y)
Therefore their ratio= 8(x+y) / 2(x+y)
                                  =4/1
Therefore Perimeter of rectangle B is 4 times perimeter of rectangleA
Hope I helped!

B.The perimeter of rectangle b  is 4 times the perimeter of rectangle a.

It is 5.8 you add all of the up to equat 180 then solve the equation