Which equation represents the function graphed on the coordinate
g(x) = |x + 4| – 2
g(x) = |x – 4| – 2
g(x) = |x – 2| – 4
g(x) = |x – 2| + 4

All equations represent the function graphed on the coordinates plane.

Step-by-step explanation:

Given :functions.

To find : Which equation represent the function graphed.

Solution : We have given that:

The parent modulus function is:

g(x) = |x|

It is centered at the origin and opens upwards.A coefficient inside the modulus |x+k| means that the function is shifted along the x-axis.

A coefficient outside the modulus |x| + h means that the function is shifted along the y-axis

Now, let's check each of the options:

g(x) = |x+4| - 2 :

This function is shifted 4 units to the left and 2 units down. It will be centered at (-4,-2). Check the blue graph in the attachment.

g(x) = |x-4| - 2 :

This function is shifted 4 units to the right and 2 units down. It will be centered at (4,-2). Check the black graph in the attachment.

g(x) = |x-2| - 4 :

This function is shifted 2 units to the right and 4 units down. It will be centered at (2,-4). Check the red graph in the attachment.

g(x) = |x-2| + 4 :

This function is shifted 2 units to the right and 4 units up. It will be centered at (2,4).

Therefore, All equations represent the function graphed on the coordinates plane.

the answer is here: : )

:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !