Write the equation of the line that contains the points (4, −7) and (1, 5). the slope of the line that contains the points (4, −7) and (1, 5) is .

 Equation of line =

The slope of the line that contains the points (4, −7) and (1, 5) is -4 .

Step-by-step explanation:

The slope of a line that contains two points (a,b) and (c,d) is given by :-

The slope of a line passing through (4, −7) and (1, 5) will be:_

The equation of a line passing through (a,b) and has slope m is given by :_

Then , the equation passing through (1,5) and has slope -4 will be

Hence, the equation of line =

The slope of the line that contains the points (4, −7) and (1, 5) is -4.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.