Fill in the blank __ pi/3 sinpi/6=1/2(sinpi/2-sinpi/6)

_ π/3 · sin π/6 = 1/2 · ( sin π/2  - sin π/6 )
Lets start from the right side of the equation:
1/2 · ( sin π/2 - sin π/6 ) = 1/2 · ( 1 - 1/2 ) = 1/2 · 1/2 = 1/4
So the left side must be equal:
_ π/3 · sin π/6 = 1/4
_ π/3 · 1/2 = 1/4
_ π/3 = 1/4 : 1/2 = 1/4 · 2/1 = 1/2
cos π/3 = 1/2

cos π/3 · sin π/6 = 1/2 ( sin π/2 - sin π/6 ) 

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