Abcd is a parallelogram. its diagonal, ac, is 18 inches long and forms a 20° angle with the base of the parallelogram. angle abc is 130°. what is the length of the parallelogram's base, ab?

The length of base of parallelogram, AB = 11.75 in

Step-by-step explanation:

ABCD is a parallelogram. Its diagonal, AC, is 18 inches long and forms a 20° angle with the base of the parallelogram. Angle ABC is 130°

Please see attachment.

In ΔABC

  ∠A+∠B+∠C=180°           (Angle sum property of triangle)

20°+130°+∠C=180°         (∴ ∠A=20° , ∠B=130° )

                ∠C=30°

Using sine law:

where, ∠C=30°, c=AB=? , b=18 , ∠B=130°

Substitute into formula

Hence, The length of base of parallelogram, AB = 11.75 in

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.