Asoftware store has put some of its inventory on sale. games are marked down by 15%, and security programs are marked down by 18%. if you pay $35.70 each for two games and $22.96 for a security program, how much have you saved?

the answer is a $17.64

Amount he saved is $17.64.

Step-by-step explanation:

Let the actual price of each game be 'x'.

Let the actual price of security program be 'y'.

Since we have given that

Games are marked down by 15%.

Security programs are marked down by 18%.

Amount paid by him on each game = $35.70

So, Amount paid by him on two games = 35.70 × 2 = $71.4

So, Price of games becomes,

Similarly,

Amount of security program paid by him = $22.96

So, Cost of security program is given by

Hence, Original price of games and security program is $84+$28=$112.

total amount he paid is given by

71.40+22.96=$94.36

So, Amount he saved is given by

Original price - Amount paid

$112-$94.36

=$17.64

seems like d

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,