The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. what is the point-slope form of the equation for this line?
a y – 13 = 5(x – 2)
b y + 13 = 5(x + 2)
c y – 2 = 5(x – 13)
d y + 2 = 5(x + 13)

The slope is 5 and.
For two lines to be parallel, both of their slopes must be the same. Therefore, our "new" line mus have the slope of 5.
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Given that we know the slope (5) and a single point (-2, -13) we stuff that into the "point slope" equation:
y - y1 = m(x - x1)
y + 13 = 5(x + 2)

What is your question?