Solve using each linear combination

5x + 2y = -4
-3x +2y = 12

a. (-2,3)
b. (0,-2)
c. (2,-7)
d. (4,0)

This question requires that you identify the point of intersection between the two line equations on a common plane. In order to solve, you can either substitute or eliminate. In this case, since neither equation is in the form of x= or y=, we will use elimination. I would suggest eliminating y, since it has the same value in both equations:
(5x + 2y) - (-3x + 2y) = 8x
-4 - 12 = -16
8x = -16
x = -2
Now that we have identified the x value that the equations intersect at, we must find the y value by plugging the found x value into either equation. In this case, I'll use the first equation, but it doesn't really matter:
5(-2) + 2y = -4
-10 + 2y = -4
2y = 6
y = 3
Now we have both the x and y value, and therefore the
(-2, 3).
The answer is A. Hope this helps!

Hello!

the answer is:

the answer is:

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!