If the length of the side of a square is 3x-y, what is the area of the square in terms of x and y?

The Area of the given square = (9x² - 6xy + y²) units²

Step-by-step explanation:

Length of the side of square = 3x - y units

Now, The all sides of the square are congruent to each other therefore, The measure of each side of the square = 3x - y

We need to find the area of the square with the given side 3x - y

Now, The area of the square is given by :

Area = (Side)²

⇒ Area of the given square = (3x - y)²

⇒ Area of the given square = (3x - y) × (3x - y)

⇒ Area of the given square = 9x² - 3xy - 3xy + y²

⇒ Area of the given square = 9x² - 6xy + y²

Therefore, The Area of the given square = (9x² - 6xy + y²) units²