Using the quadratic formula to solve x2 = 5 – x, what are the values of x?

Hello : 
the discriminat of each quadratic equation : ax²+bx+c=0 (a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
in this exercice : x² = 5-x
x² +x-5 = 0     a =1   b= 1   c=-5
calculate Δ

The answer to your question is b’(16,14)