State the x-coordinate of the x-intercept in quadrant ii for the function below.
f(x)=x^3-x^2-x+1

ANSWER

The x-coordinate of the x-intercept of the function is .

EXPLANATION:

The x-intercept refers to the point where the function meets or cuts the x-axis.

At the x-intercept, .

This means we have to equate the whole function to zero and solve for .

According to the rational roots theorem, the possible rational roots of the equation are .

We now plug in these possible rational roots to see which of them are real roots.

Since , is a root.

By the factor theorem, is a factor of the function.

We now divide the polynomial function,   by   to find the remaining roots.

See long division in diagram.

This means that .

Or

Hence the roots are or

In the second quadrant the x-coordinate is negative

Therefore, the x-coordinate of the x-intercept of the function is .

See graph in attachment

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

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step-by-step explanation: