The sum of one-third of a number and three-fourths of the number exceeds that number by one. which equation could be used to find the number? n = n + 1 n + n = n - 1 n + n = n + 1

+ = n +1.

Number = 12.

Step-by-step explanation:

Given : The sum of one-third of a number and three-fourths of the number exceeds that number by one.

To find : Which equation could be used to find the number.

Solution : We have given a statement

Let a number  = n

According to question

One third of a number = .

Three - fourths of the number  =  .

Sum of their is  exceeds that number by one.

+ = n +1.

Taking common denominator

= n+1 .

= n+1.

On subtracting n both sides.

-n = 1

Taking common denominator

= 1

= 1

On multiplying by 12 both sides

n= 12.

Therefore, + = n +1.

Number = 12.

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

i need a picure

step-by-step explanation: