Ataxicab starts at (1, -2) on the grid. it goes 4 blocks south and 3 blocks east to pick up a passenger. then it goes 6 blocks west and 5 blocks north and drops off the passenger. how many blocks is the taxicab from its starting position

The cab is -1/3 west of north.

( from the starting point it goes 1 block to the north and 3 blocks to the west . Cab is at (-2,-1))

Step-by-step explanation:

It is given that:

A taxicab starts at (1, -2) on the grid.

This implies that the cab will reach at a point (4,-6)

( Since going south means it will go some units down and similarly going east means it will go some units to the right.

Hence, here going 4 blocks south and 3 blocks east means it will go to:

(1,-2) → (1+3,-2-4)=(4,-6) )

This means that the cab will drop the passenger at (-2,-1)

Since going north means it will go some units up and similarly going west means it will go some units to the left.

Hence, here going 6 blocks west and 5 blocks north means it will go to:

(4,-6) → (4-6,-6+5)=(-2,-1) )

Hence, the end point is (-2,-1)

Now the slope of the line joining the starting and the end point is:

i.e. line joining (1,-2) and (-2,-1) is:

Hence, the taxicab is -1/3 block west of north.

i.e. from the starting point it goes 1 block to the north and 3 blocks to the west.

i.e. the cab is in west-north direction from the starting point.

where r the answers

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.