Sec theta = 5/3 and the terminal point determined by quadrant 4

Here, we have

Since

So, for the angle θ,

Hypotenuse = 5 and Base = 3

Using Pythogoras theorem,

(Hypotenuse)² = (Base²) + (Perpendicular )²

(5 )² = ( 3 )² + (Perpendicular )²

⇒ Perpendicular = 25 - 9 = √16 = 4

we have given θ lie in IV quadrant. In IV quadrant cos and sec are positive function but sine, cosec, tan and cot are negative.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

(3x-8) or (3x+8)

step-by-step explanation: