The track team has 11 distance runners but can only enter five in the meet. how many combinations of five runners can the coach create? 462; 120; 55,440; 3,696

The answer is D. 462. We used the combination formula. It tells the number of combination for (r) objects from a set of (n) objects. it is written as nCr = n! / r! (n-r)!. If we substitute the given to the formula, we will have 11C5. By evaluating 11! / (5!(6!)) we will obtain 462

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

if x = 1, then the answer is 3.5