Apoint is selected at random inside the given figure.
what is the probability the point will be in the region labeled a?
enter your answer, as a fraction in simplest form, in the box.
p(a) =

need !

Area of region A = (length)*(width) = 7*5 = 35 square inches

Area of region B = (length)*(width) = 3*4 = 12 square inches

Area of region C = (length)*(width) = 4*4 = 16 square inches

Area of region D = (length)*(width) = 3*9 = 27 square inches

Overall, the four regions combine to a total area of 35+12+16+27 = 90 square inches

Of that total area, region A only takes up 35 square inches of that

P(A) = (area of region A)/(total area)
P(A) = 35/90
P(A) = 7/18

The final answer is 7/18