How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

The function comes from the base function y= sec(x).  

Since 3 is added added on the inside, this  is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift  down 7 units.

Therefore, the transformation on the given function is shifted  3 units left and 7 units down

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