and:
![\left(\star\right)=\dfrac{2\pi}{15}\cdot\int\limits_0^{15}x^3\cdot\sqrt{1+\dfrac{x^4}{25}}\,\, dx=\dfrac{2\pi}{15}\cdot\dfrac{25}{6}\cdot\left[\left(1+\dfrac{x^4}{25}\right)^\frac{3}{2}\right]_0^{15}=\\\\\\= \dfrac{5\pi}{9}\left[\left(1+\dfrac{15^4}{25}\right)^\frac{3}{2}-\left(1+\dfrac{0^4}{25}\right)^\frac{3}{2}\right]=\dfrac{5\pi}{9}\left[2026^\frac{3}{2}-1^\frac{3}{2}\right]=\\\\\\= \boxed{\dfrac{5\Big(2026^\frac{3}{2}-1\Big)}{9}\pi}](/tpl/images/0409/9104/b6fc8.png)
99 point question, plus !
( answer genuinely, and do not answer just for points, if you do, y...
Mathematics, 09.12.2019 10:31 Jasten
99 point question, plus !
( answer genuinely, and do not answer just for points, if you do, your answer will be deleted, and those points you earned will be taken
this is calculus not basic
14.) find the area of the surface generated by revolving the curve about the x-axis.
[use attachment below]
** show all of you work, if you do not, your answer will be deleted, and the points you earned will be taken
** if you do not know how to show your work, and/or believe it is "too complex to show", show me how to set up the problem, and the answer to the problem
Answers: 1
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