An initial population of 640 quail increases at a annual rate of 18%. write an exponential function to model the quail population
( a). f(x)=640(1.18)^x
(b). f(x)=640 (0.18)^x
(c). f(x)= (640×0.18)^x
(d). f(x) =640 (18)^x

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

98%

step-by-step explanation:

(x) - (y) = (1 + 4i)