Ablock of wood weighing 18 pounds rests on an inclined plane that makes an angle of 60 with the horizontal. how much of the friction force is needed to prevent the block from sliding on the plane?
round answer to nearest whole number. do not use a space or decimal in your answer or it will be marked wrong

Force of friction will be 69 N

Step-by-step explanation:

Given a block of wood weighing 18 pounds rests on an inclined plane that makes an angle of 60 with the horizontal. we have to find the force of friction needed to prevent the block from sliding on the plane.

As the plane makes an inclination, vertical force will act on the wood to slide. Therefore, the friction force must be equal to vertical force so that the wood not to slide.

 where F is friction force, m is weight of an object and is inclination angle made from the horizontal.

As 1 pound=0.453592 kg

∴ 18 lbs = 8.165 kg

         = 8.165 x 9.8 x sin 60°

         = 69.29 N ≈ 69 N  

lo.lll

step-by-step explanation:

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake