Aball is thrown upward from the top of a building. the function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

f(t) = −16t2 + 48t + 100

the average rate of change of f(t) from t = 3 seconds to t = 5 seconds is per second.

answer: the average rate of change of f(t) from t = 3 seconds to t = 5 seconds is -40 feet per second.

step-by-step explanation: xx

given: a ball is thrown upward from the top of a building. the function below shows the height of the ball in relation to sea level, f(t), in feet, at different times, t, in seconds:

now,

now, the   average rate of change of f(t) from t = 2 to t = 6 is given by : -

therefore, the average rate of change of f(t) from t = 3 seconds to t = 5 seconds is -40 feet per second.

First, we differentiate the equation for the distance so to find the velocity in feet per second (ft/s).
                                f(t) = -16t² + 48t + 100
differentiating,
                              df(t)/dt = -32t + 48
the value at t = 3 is,
                            df(t) / dt = -32(3) + 48 = -48 ft/s
the value at t = 5 is
                            df(t) / dt = -32(5) + 48 = -112 ft/s

the average of both values is -80 ft/s. 

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