An infinite geometric series has 1 and 1/5 as its first two terms: 1, 1/5, 1/25, 1/125, . . what is the sum, s, of the infinite series? a. 1 b. 5/4 c. 1/4 d. 1/25

Step-by-step explanation:

Given: The first term of Geometric series : a=1

The seconds term of Geometric series :

The common ratio between the terms is given by :-

We know that the sum of infinite geometric series is given by :-

Hence, the sum of the given infinite series =

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

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