Aprojectile is launched with an initial speed of 42 feet per second. it is projected at an angle of 50 degrees. how far does the projectile travel? how much farther does it travel if it is launched with an initial speed of 84 feet per second?

1) 53.95 ft ( approx )

2) 161.85 ft. ( approx )

Step-by-step explanation:

Given,

Initial velocity,

Also, the projected angle,

1) Thus, the distance travelled horizontally ( Range of the projectile motion ),

Where, g is the acceleration due to gravity that having the value 32.2 ft per second,

Hence, the projectile covers 53.95 feet ( approx )

2) If

Then the range would be,

Thus, the additional distance = 215.80 ft - 53.95 ft = 161.85 ft.

Hence, It will travel 161.85 ft extraa.

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.