2. simplify the radical expression
√56x²

a. 28x
b. 2x√14
c. 2x√7
b. 2√14x²

3. simplify the radical expression
√250h^4 k^5

a. hk√125
b. 5√10h^4 k^5
c. 5h² k²√10k
d. 25hk√10k

4. simplify the radical expression
√15y • 3√81y

a. 2√135y²
b. 2y√135
c. 27√15y²
d. 27√15

2.  sqrt56x^2 =  sqrt4*14*x^2 = 2x sqrt14 LETTER B
3.  sqrt250h^4k^5 = sqrt 25*10*h^4*k^4*k = 5h^2k^2 sqrt10k LETTER C
4.  sqrt15y  * 3sqrt81y = sqrt15y * 27sqrt y =    27sqrt15y^2  LETTER C

So! first off, it's important to understand the idea that if you have a bunch of things multiplied together under a root:

√abc

you can take the root of EACH of those parts, and multiply them together.

√abc = √a√b√c

so if you understand that, simplifying your problems are pretty straightforward. please let me know if you need the above idea clarified.

so, now looking at your specific problems:

1. √56x^2

first, we see two things multiplied together, x^2 and 56. let's take the root of EACH part.

=√56√x^2

let's first talk about simplifying √56
to do this, we need to do the prime factorization of what's within, or 56. this just means splitting up 56 into a bunch of prime numbers multiplied together. usually this is done with a "tree".

56 can first be split up into 8 and 7, since 8×7 is 56. 7 is prime so we're done there. 8 is NOT prime though, so let's split it up further. 8 can be split up into 4 and 2, and 4 can be split to 2 and 2. I WOULD draw the tree here, but I can't haha. basically:

56= 8×7
56= 4×2×7
56=2×2×2×7

since both 2 and 7 are prime, this is the prime factorization of 56. alright! from this, we can say:

√56 = √2×2×2×7

I'm gonna do something now, please comment if this doesn't make sense. I'm gonna take two of those 2's and put them under a root by themselves.

√2×2×2×7 = √2×2√2×7

remember our rule--if things are multiplied, we can pull them apart. However, why did we do this? well, notice what 2×2 equals. It's 4, right? And what is the square root of 4? 2!

so,

√2×2×2×7 = 2√2×7

to summarize this, if you have a number under a SQUARE root, your gonna split up that number until you get a "perfect square". then, you're gonna simplify that part, and leave the rest under a SQUARE root. that's how you simplify something like this. so,

√56 = 2√2×7 = 2√14

alright! So, first part done. now we gotta do

√x^2

remember our √2×2? it ended up being 2 right, or the number being multiplied under the square root. apply this idea to the variable. we're taking the square root of x^2. so, were looking for a value, when multiplied by itself, gives us x^2. I'm just gonna say it, but if you need more explanation id be happy to go more in depth. the answer here would just be x.

so! finally:

√56x^2 = 2x√14 or B

I would be happy to assist with the rest of your questions, but I believe you have the tools now to do so. let me know if you need more help!