Let a and b be real numbers where a ≠ b ≠ 0. which of the following functions could represent the graph below?
(x) = x(x – a)2(x – b)4

f(x) = x(x – a)3(x – b)2

f(x) = x4(x – a)(x – b)2

f(x) = x2(x – a)5(x – b)

The correct answer is option (C), that is,

Step-by-step explanation:

From the given graph, we can see that the left most point where graph meets axis is the point where graph touches the x axis. Therefore, the factor corresponding to that point must have an even multiplicity. Therefore, exponent of one of (x-a) or (x-b)  must be even.

Further, at x=0, the graph touches x axis. Therefore, multiplicity of this zero must be even as well. This implies that exponent of x must be even.

Finally, at right most zero, we can see that the graph cross x axis, without staying on x axis. Therefore, multiplicity of that particular zero must be odd and more accurately it should be 1.

Combining all these factors together, we can conclude that one of (x-a) and (x-b) must have an exponent 1 and other must have an even exponent. At the same time x must have an even exponent. All these conditions are satisfied by the function . Here, x has an even exponent (4). (x-a) has exponent 1 and (x-b) has an even exponent (2). Therefore, correct answer is option (c).

ha!

i just did this!

18. g

20. h 30 degree turn.

21. d 90 degree angles

and also 19 is a. a sphere not a cirlcle

hope i !

pls mark me brainiest

triangle and cube

step-by-step explanation: