What are the coordinates of the image of point (-1,5) after a counterclockwise rotation of 90* about the origin

In general when a point is rotated through 90° counterclockwise about the origin, first notice in which quadrant the image of the point is located. Suppose the image of point P (h, k). When you rotate it through 90° counterclockwise it takes the image M' (k, -h)
In the example M(-1,5) : it's located in the 2nd quadrant & if you  rotate it through 90° counterclockwise M' will be located in the third quadrant where both h & k are negative. So M'(-5,-1)

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote