Find the lcd of the fractions, and then simplify the expression. assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3
show all the steps so you can me understand

The LCD = 6x^2y^3    ( because LCD of 3 and 6 = 6,  LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD  then multiply this  by 5 to get the first term in the numerator  and do similar process to get second term, so we get:-

5(2y^2) - 4(x)

   6x^2y^3

=  2( 5y^2 - 2x)
   
        6x^2y^3

=    5y^2 - 2x
     
      3x^2y^3

Magic man is here, but unfortunately he is broke won’t you him out

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