What is the focus of the parabola? y=14x2−x−1
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This is a vertical parabola which opens upwards
we have the general formula
(x - h)^2 = 4p(y - k)   where p is the  y coordinate of the focus

y/14 = x^2 - x /14 - 1/14

add 1/14 to both sides

y/14 + 1 /14 = x^2 - x /14

now complete the square  

y/14 + 1/14 = x^2 - x/14  + 1/28^2

y/14 + 1/14 = (x - 1/28)^2

(x - 1/28)^2 = 1/14( y + 1)

comparing this with the general form:-
4p = 1/14
p =  1/56

so the focus is at (h,p) = (1/28, 1/56)