find the surface area of the composite solid if the base is a regular hexagon. round your answer to the nearest hundredth.
a.
471.53 m2
b.
615.53 m2
c.
709.06 m2
d.
802.59 m2

The answer is B. 615.53 m2.

The surface area (SA) is the sum of base area (A1), 6 areas of rectangle with sides 6 m and 7m (A2), and 6 areas of triangles with sides 15 m and 6 m (A3):
SA = A1 + 6A2 + 6A3

A1 = 3√3 * a² / 2
a = 6 m
A1 = 3√3 * 6² / 2 = 3√3 * 36 / 2 = 54√3 = 93.53 m²

A2 = a * b
a = 6 m
b = 7 m
A2 = 6 * 7 = 42 m²

A3 = a * h / 2
a = 6 m
h = 15 m
A3 = 6 * 15 / 2 = 45 m²


SA = A1 + 6A2 + 6A3
SA = 93.53 + 6 * 42 + 6 * 45 = 93.53 + 252 + 270 = 615.53 m²