Ajar contains several colors of jelly beans. there are red, green, black, and yellow jelly beans in the jar. you pick one jelly bean at a time, record what color you picked, and then replace the jelly bean. you do this 30 times and get the following results.

there are 5 red, 15 green, 7 black, 3 yellow.

a. 0.3
b. 0.30
c. 0.90
d. 0.10

Option D.

Step-by-step explanation:

The question is: which is the probability of selecting a yellow jelly bean?

The data that we have is that, at random selection, we got:

5 times red

15 times green

7 times black

3 times yellow.

This means that out of 5 + 15 + 7 + 3 = 30 attempts, in 3 of them we got a yellow jelly bean, then the probability can be calculated as:

P = (number of times we got a yellow bean)/(total number of attempts)

P = 3/30 = 0.10

the correct option is D

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

one set of data has more variation than the other. hope this !