The first barn contained 3 times more hay than the second one. after 20 tons of hay were removed from the first barn and 20 tons were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn. how many tons of hay was there in each barn?

The solution would be like this for this specific problem:

a + 20 = 5/7 (3a - 20) 
a + 20 = (15a - 100)/7 
Multiply both side by 7, 
7a + 140 = 15a - 100 
8a = 240 
a = 30

3a = 90

a + 20 = 50

3a - 20 = 70

y= -

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.