If m angle acd = 120- x, m angle b = 60, and m angle a = 10 + x, find m angle acb

 I have no idea what this question means. If it is purely algebraic then this is impossible unless D is known. I suppose ACB could be written as 60(120-x)/D, but I doubt that is much help. 

If this is an angles question, then the shape that the angles are within needs defining, as do the letters. For instance if ACD represents an angle, then the vertices must have been labelled A,B,C,D, but then it makes no sense to be defining A or B. Similarly, if A, B are side lengths, then ACD and ACB aren't useful. I'm very confused as to how this can be approached, without further information or a diagram.

The answer is a good luck