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Let f(x)=x2βxβ30 . what are the zeros of the function?
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The parabola y = xΒ² - 4 opens: a.) up b.) down c.) right d.) left
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Graph y β₯ -x^2 - 1. click on the graph until the correct graph appears.
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Atriangle has verticals at b(-3,0), c(2,-1), d(-1,2). which transformation would produce an image with verticals bβ(-2,1), cβ(3,2), dβ(0,-1)?
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Let f(x)=x2βxβ30 . what are the zeros of the function?...
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