Factor to find the zeros of the function defined by the quadratic expression. 2x2 − 18x + 36 a) x = 3 or x = 6 b) x = 3 or x = −6 c) x = −3 or x = 6 d) x = −3 or x = −6

A) x=3 or x=6

Step-by-step explanation:

Factor out the GCF : 2(x^2-9x+18)

Then, set to zero.

2(x^2-9x+18)=0

2(x-3)(x-6)=0

x=3 or x=6

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

i will u if u answer my question in math