Me pretty .
i have 2 questions.

Ok first one since they have like terms in the denominator just cancel those and you will be left with x^2=9, now subtract 9 from both side to get x^2-9=0 now find the common factors.. we need to find a number that is the same and can be multiplied to get -9 and added and subtracted to eliminate it.. 3 times -3 gives you -9 and if you add or subtract them they eliminate themselves.. so our factors will be (x-3)(x+3) now set each set equal to zero to get the final answer of x. x-3=0 add 3 to both sides to get x=3 now with x+3=0 subtract 3 from both sides and you will get x=-3 so our both sets of number for x are 3,-3 so your answer for the first one is the second option.

for the second I am stuck I don't understand sorry!!!

I believe that the second answer is c -5, 3.