Given a circle with measures of (c, d, and r) and a circle with measures of (c', d', and r'), what is r' if c c' = 3.0 and d = 12.0?

a) 2
b) 4
c) 8
d) 12

edit: the answer is a) 2

we know that

The circumference of a circle is equal to

where

D is the diameter of the circle

In this problem we have

the circumference of the circle is

------> equation A

the circumference of the circle is

------> equation B

and the ratio of the circumference of the circle to the circumference of the circle is

------> equation C

Substitute the equation A and equation B in the equation C

Find the radius r'

therefore

the answer is  the option A

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: