Abag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. two marbles are chosen from the bag. what expression would give the probability that one marble is yellow and the other marble is red? p(y and r) = p(y and r) = p(y and r) = p(y and r) =

P(Y and R)=

Step-by-step explanation:

A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Two marbles are chosen from the bag

To marbles are chosen, one marble is yellow and other marble is red

so we take the intersection of yellow and red

The expression would be P( yellow  and Red) that is

P(Y  and R)

eight yellow marbles, nine green marbles, three purple marbles, and five red marbles.  total marbles = 25 marbles

P(choosing yellow marble)= 8/25

P(choosing red marble)= 5/24

P(Y and R)=

the answer is 8/21

hope this