Will give brainliest

a vehicle travels a distance of of 5t^4-10t^2+6 miles in t+2 minutes.

what is the vehicles speed?

a. 5t^3+10t^2+10t+20+(46)/(t-2))
b. 5t^3-10t^2+10t+20+46
c. 5t^3-10t^2+10t-20+(46)/(t+2))
d. 5t^3+10t^2+10t+20+(46)/(t+2))

Speed = Distance / Time

Distance = 5t^4 - 10t^2+6

Time = t+2

Now:

 5t^4 - 10t^2 + 6         | t+2
-5t^4 -10t^3                 5t^3 - 10t^2 + 10t - 20
  -10t^3-10t^2+6
       +10t^3+20t^2
        10t^2+6
                -10t^2-20t
                  -20t+6
                      +20t+40
                        46

C. 5t^3-10t^2+10t-20+(46)/(t+2))

Ais the answer for your question