An isosceles trapezoid has base angles of 45° and bases of lengths 9 and 15. the area of the trapezoid is

The difference in the bases is 15-9=6.  Since the base angles are 45°, the height of the trapezoid is equal to half of that difference, so the height is 3 units.  The area of a trapezoid is:

A=h(b1+b2)/2 so in this case:

A=3(9+15)/2

A=36 u^2

Ithink your answer is c hope that