Mathematics, 12.10.2019 03:30 sbhishop19
Factor completely 2x3y4 − 8x2y3 + 6xy2. 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) prime
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is common among all the terms hence we write this term out of the parantheses and the remaining term inside it as to obtain then simplified expression as:
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Factor completely 2x3y4 − 8x2y3 + 6xy2. 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy...
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