(07.05 hc)
the work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below:
step 1: 3(3y − 8) = 10 + 3y
step 2: 6y − 5 = 10 + 3y
step 3: 3y − 5 = 10
step 4: 3y = 15
step 5: y = 5
in which step did the student first make an error and what is the correct step?
step 2: 9y − 24 = 10 + 3y
step 2: 6y + 11 = 10 + 4y
step 3: 6y − 8 = 3(6 + y)
step 3: 3(3y − 8) = 7 + y