Write (3i - 2/3) - (6i-5) as a complex number in standard form. i have no idea what im doing to be honest give me pointers or hints or anything to me get this done . : )

so, the standard form is:  

Step-by-step explanation

The standard form of a complex number is given in the form of:

where a,b belongs to real numbers.

we are given the expression in complex number as:

on combining the like terms i.e. on combining the real and imaginary part of the complex number we get,

Hence, on comparing our number with the standard form of the complex number we get

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

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