Hugh uses 0.63 of a piece of canvas to paint a picture. draw a model to represent this decimal. how much of the canvas is left?

The required figure or model which represents 0.63 is shown in figure 1. Hugh left with 0.37 piece of canvas.

Step-by-step explanation:

Consider the provided information.

We need to draw a model to represent this decimal.

We can use girds to write fraction and decimal.

0.63 is the same as

These decimal and fraction are equivalent.

Now draw 100 grids and shade 63 out of them.

As shown in figure 1:

The figure 1 represents 0.63 or .

The shaded are represents the 63 and there are total 100 grids out of which 37 grids are not shaded.

Hence, Hugh left with 0.37 piece of canvas.

The required figure or model which represents 0.63 is shown in figure 1. Hugh left with 0.37 piece of canvas.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.