Acertain species of fish has been declining in population by 7% per year. that means its rate of decay is 0.93. the population at time zero is 500,000. to the nearest whole year, which year will the population of the fish be close to 300,000?

Do you have a graphing calculator, or have access to an online one? If so, you just have to put in the expression y = 500,000(0.93)^x. From there, you look where the line would have a y value of near 300,000. Then you see which x value that lies on.