equation a: y = 15 β 2z
Mathematics, 27.01.2020 07:31 krystynas799
The work of a student to solve a set of equations is shown:
equation a: y = 15 β 2z
equation b: 2y = 3 β 4z
step 1: β2(y) = β2(15 β 2z) [equation a is multiplied by β2.]
2y = 3 β 4z [equation b]
step 2: β2y = 15 β 2z [equation a in step 1 is simplified.]
2y = 3 β 4z [equation b]
step 3: 0 = 18 β 6z [equations in step 2 are added.]
step 4: 6z = 18
step 5: z = 3
in which step did the student first make an error?
step1
step 2
step 3
step 4
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The work of a student to solve a set of equations is shown:
equation a: y = 15 β 2z
equation a: y = 15 β 2z
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